Students can Download Maths Chapter 10 Exponents Ex 10.4 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka Board Class 8 Maths Chapter 10 Exponents Ex 10.4

Question 1.

Simplify

(i) \(\frac{\left(2^{5}\right)^{6} \times\left(3^{3}\right)^{2}}{\left(2^{6}\right)^{5} \times\left(3^{2}\right)^{3}}\)

(ii) \(\frac{\left(5^{-3}\right)^{2} \times 3^{4}}{\left(3^{-2}\right)^{-3} \times\left(5^{3}\right)^{-2}}\)

Answer:

Question 2.

Can you find two integers m and n such that 2m+“ = 2m”?

Answer:

m + n = mn

2 + 2 = 2 x 2

4 = 4

∴ m = 2 & n = 2

Question 3.

If (2^{m})^{4} = 4^{6} find the value of m.

Answer:

(2^{m})^{4} = 4^{6} (a^{m})^{n} = a^{mn}

(2^{m})^{4} = 4^{6}

(2^{m})^{4} = (2^{2})^{6}

2^{m × 4} = 2^{2 × 6}

2^{4m} = 2^{12}

∴ 4m = 12

m =

m = 3