KSEEB Solutions for Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3

Students can Download Maths Chapter 2 Algebraic Expressions Ex 2.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka Board Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3

Question 1.
Complete the following table of products of two monomials

First →
Second ↓
3x-6y4x2– 8xy9x2y-11 x3y2
3x9x2-18xy12x3-24x:y27x3y-33x4y2
-6y-18xy36y2-24x2y48xy--54x2y266x3y3
4x-I2x3-24x2yI6x4-32x3y236x4y-44x3y2
-8xy-24x2y48xy2-32x3y64x2y2-72x3y288x4y3
9x2y27x3y-54x2y236x4y-72xy81x4y2-99 x3y3
-11 x3y2-33x4y366 x2y3-44 x5y288 x4y3-99 x5y3121 x6y4

Question 2.
Find the products
i. (5x + 8) 3x
ii. (-3 pq)(-15 p3q² – q3)
iii. \(\frac{2 x}{5}\left(3 a^{3}-3 b^{3}\right)\)
iv. -x²(x – 15)
Answer:
i. 5x . 3x + 8.3x = 15x² + 24x

ii. (- 3pq) (- 15p3q² – q3)
= (- 3pq) (- 15p3q²) – (- 3pq)(q3)
= 45 p4q3 + 3 pq4

a

iii. \(\frac{2 x}{5} \times 3 a^{3}-\frac{2 x}{5} \times 3 b^{3}=\frac{6 x a^{3}}{5}-\frac{6 x b^{3}}{3}\)

iv. (-x²)x – (-x²) 15
= -x3 + 15x²

Question 3.
Simplify the following :
i. (2xy -xy) (3xy – 5)
ii. (3xy² +1) (4xy – 6xy²)
iii. (3x² + 2x) (2x² + 3)
iv. (2m3 + 3m) (5m – 1)
Answer:
i. 2x y (3xy – 5) – 2xy(3xy – 5) = 6x²y² – 10xy – 6x²y² + 10xy

ii. 3xy² (4xy – 6xy²) +1 (4xy – 6xy²) = 12 x²y3 – 18x²y4 + 4xy – 6xy²

iii. 3x²(2x² + 3) + 2x(2x² + 3] = 6x4 + 9x² + 4x3 + 6x

iv. 2m(5m – 1) + 3m(5m – 1) = 10m4 – 2m+ 15m² – 3m

a