Students can Download Chapter 6 Integers Ex 6.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka State Syllabus Class 6 Maths Chapter 6 Integers Ex 6.3

Question 1.

Find

Solution:

a) 35 – (20)

35 – (20) = 15

b) 72 – (90)

72 – (90) = -18

c) (-15) – (-18)

(-15) – (-18) = -15 + 18 = 3

d) (-20) – (-13)

(-20) – (-13) = -33

e) 23 – (-12)

23 – (-12) = 23 + 12 = 35

f) (-32) – (-40)

(-32) – (-40) = -32 + 40 = 8

Question 2.

Fill in the blanks with >,< or = sign

a) (-3) + (-6) ___ (-3) – (6)

(-3) + (-6) = -9

(-3) – (-6) = -3 + 6 = 3 – 9 < 3

Hence (3) +(-6) < (-3)-(-6) b) (-21) – (-10) ___ (-31) + (-11) -31 + (-11) = -42 – 11 > -42

(9 – 21) – (- 10) ≥ (-31) +(-11)

c) 45 – (-11) ___ 57 + (-4)

57 + (-4) = 57 – 4 = 53

56 > 53

d) (-25) – (-42) ___ (-42) – (-25)

-42 – (-25) = -42 + 25 = -17

117 > -17

(-25) – (-42) ≥ (-42) – (-25)

Question 3.

Fill in the blanks

a) (-8) __+ 8__ = 0

b) 13 + __(-13)__ = 0

c) 12 + (- 12) = __0__

d) (-4) + __(-8)__ =-12

e) __5__ – 15 = -10

Question 4.

Find

Solution:

a) (-7) -8 – (-25)

(-7) – 8 – (-25) = (-7) – 8 + 25 = -15 + 25 = 10

b) (-13) + 32 – 8 – 1

(-13) + 32 – 8 – 1 = -13 + 32 – 8 – 1 = 32 – 22 = 10

c) (-7) + (-8) +(-90)

(-7) + (-8) + (-90) = -7 – 8 – 90 = -105

d) 50 – (-40) – (-2)

50 – (-40) – (-2) = 50 + 40 + 2 = 92