KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3

You can Download KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Questions and Answers to help you to revise the complete syllabus.

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3

Question 1.
Carry out the following divisions.
(i) 28x4 ÷ 56x
(ii) -36y3 ÷ 9y2
(iii) 66pq2r3 ÷ 11qr2
(iv) 34x3y3z3 ÷ 51xy2z3
(v) 12a8b8 ÷ (-6a6b4)
Solution:
KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q1

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q1.1

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q1.2

Question 2.
Divide the given polynomial by the given monomial.
(i) (5x2 – 6x) ÷ 3x
(ii) (3y8 – 4y6 + 5y4) ÷ y4
(iii) 8(x3y2z2 + x2y3z2 + x2y2z3) ÷ 4x2y2z2
(iv) (x3 + 2x2 + 3x) ÷ 2x
(v) (p3q6 – p6q3) ÷ p3q3
Solution:
KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q2

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q2.1

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q2.2

Question 3.
Work out the following divisions.
(i) (10x – 25) ÷ 5
(ii) (10x – 25) ÷ (2x – 5)
(iii) 10y(6y + 21) ÷ 5(2y + 7)
(iv) 9x2y2(3z – 24) ÷ 27xy(z – 8)
(v) 96abc(3a – 12) (5b – 30) ÷ 144(a – 4) (b – 6)
Solution:
KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q3

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q3.1

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q3.2

Question 4.
Divide as directed.
(i) 5(2x + 1) (3x + 5) ÷ (2x + 1)
(ii) 26xy(x + 5) (y – 4) ÷ 13x(y – 4)
(iii) 52pqr(p + q) (q + r) (r + p) ÷ 104pq(q + r) (r + p)
(iv) 20(y + 4) (y2 + 5y + 3) ÷ 5(y + 4)
(v) x(x + 1) (x + 2) (x + 3) ÷ x(x + 1)
Solution:
KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q4

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q4.1

Question 5.
Factorize the expressions and divide them as directed.
(i) (y2 + 7y + 10) ÷ (y + 5)
(ii) (m2 – 14m – 32) ÷ (m + 2)
(iii) (5p2 – 25p + 20) ÷ (p – 1)
(iv) 4yz(z2 + 6z – 16) ÷ 2y(z + 8)
(v) 5pq(p2 – q2) ÷ 2p(p + q)
(vi) 12xy(9x2 – 16y2) ÷ 4xy(3x + 4y)
(vii) 39y3(50y2 – 98) ÷ 26y2(5y + 7)
Solution:
KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q5

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q5.1

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q5.2

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q5.3

KSEEB Solutions for Class 8 Maths Chapter 14 Factorization Ex 14.3 Q5.4