You can Download KSEEB Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.3 Questions and Answers to help you to revise the complete syllabus.

## KSEEB Solutions for Class 8 Maths Chapter 5 Data Handling Ex 5.3

Question 1.

List the outcomes you can see in these experiments.

(a) Spinning wheel

Solution:

(a) Outcomes in the spinning wheel are A, B, C, and D.

Question 2.

When a disc is thrown, list the outcomes of an event of getting

(i) (a) a prime number

(b) not a prime number.

(ii) (a) a number greater than 5

(b) a number not greater than 5

Solution:

(i) (a) A prime number 2, 3, 5

(b) Not a prime number 4, 6

(ii) (a) A number greater than 5 = 6

(b) A number not greater than 5 = 1, 2, 3, 4

Question 3.

Find the:

(a) Probability of the pointer stopping on D in [Question 1-(a)]?

(b) Probability of getting an ace from a well-shuffled deck of 52 playing cards?

(c) Probability of getting a red apple. (See figure below)

Solution:

(a) Number of possible outcomes for pointer stopping on

D = 1

Total number of outcomes of the experiment = 5

∴ Probability of pointer stopping at D = \(\frac{1}{5}\)

(b) Total number of aces = 4

Total number of outcomes = 52

P(an ace) = \(\frac{4}{52}=\frac{1}{13}\)

(c) Number of Red apples = 4

Total number of outcomes = 7

∴ P of getting a red apple = \(\frac{4}{7}\)

Question 4.

Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of:

(i) getting a number 6?

(ii) getting a number less than 6?

(iii) getting a number less than 6?

(iv) getting a 1-digit number?

Solution:

(i) Number of slip written 6 on it = 1

Total number of outcomes = 10

∴ P (getting 6 on a slip) = \(\frac{1}{10}\)

(ii) Number less than 6 are = 1, 2, 3, 4, 5 = 5

Total number of slips = 10

∴ P(getting a number less than 6) = \(\frac{5}{10}=\frac{1}{2}\)

(iii) Number greater than 6 are = 7, 8, 9, 10 = 4

Total number of slips = 10

∴ P (getting a number greater than 6) = \(\frac{4}{10}=\frac{2}{5}\)

(iv) One digit numbers are = 1, 2, 3, 4, 5, 6, 7, 8, 9

Total numbers = 10

∴ P (of one digit number) = \(\frac{9}{10}\)

Question 5.

If you have a spinning wheel with 3 green sectors, 1 blue sector, and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non-blue sector?

Solution:

Total sectors = 3 + 1 + 1 = 5

Number of green sectors = 3

Number of non-blue sectors = 3 + 1 = 4

∴ P(of getting a green sector) = \(\frac{3}{5}\)

∴ P (of getting a non blue sector) = \(\frac{4}{5}\)

Question 6.

Find the probabilities of the events given in Question 2.

Solution:

(i) (a) P(a prime number) = \(\frac{3}{6}=\frac{1}{2}\)

(b) P(not a prime number) = \(\frac{2}{6}=\frac{1}{3}\)

(ii) (a) P(a number greater than 5) = \(\frac{1}{6}\)

(b) P(a number not greater than 5) = \(\frac{4}{6}=\frac{2}{3}\)