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## Karnataka State Syllabus Class 5 Maths Chapter 9 Perimeter and Area

### KSEEB Class 5 Maths Perimeter and Area Ex 9.1

I. Answer orally:

Question 1.

What are two-dimensional figures called?

Answer:

Plane figures

Question 2.

Name the two dimensions of a rectangle.

Answer:

Length and breadth

Question 3.

How many pairs of opposite sides are there in a rectangle?

Answer:

Two pairs

Question 4.

How are the opposite sides in a rectangle?

Answer:

Equal

Question 5.

How many times is the perimeter of a rectangle to the sum of its length and breadth?

Answer:

Twice

II. Find the perimeter of the following pictures:

Perimeter of Rectangle = (21 + 2b)

= (2 × 70 + 2 × 90)

= 140 + 180

= 320 cm

Perimeter of Rectangle = (21 + 2b)

= (2 × 60 + 2 × 24)

= 120 + 48

= 168 cm

Perimeter of Rectangle = (21 + 2b)

= (2 × 153 + 2 × 122)

= 306 + 244

= 550 cm

Perimeter of Rectangle = (21 + 2b) units

= (2 × 3 + 2 × 6)

= 6+12

= 18cm

Perimeter of Rectangle

= (21 + 2b)

= (2 × 92 + 2 × 80)

= (184 + 160)

= 344 cm

III. The length and breadth of rectangles are given below. Find their perimeters.

1) The Perimeter of Rectangle = (21 + 2b)

= (2 × 2 + 2 × 3)

= 4 + 6

= 10 cm

2) The Perimeter of Rectangle = (21 + 2b)

= (2 × 2 + 2 × 4)

= 4 + 8

= 12 cm

3) The Perimeter of Rectangle = (21 + 2b)

= (2 × 3 + 2 × 4)

= 6 + 8

= 14 cm

4) The Perimeter of Rectangle = (21 + 2b)

= (2 × 5 + 2 × 4)

= 10 + 8

= 18 cm

5) The Perimeter of Rectangle = (21 + 2b)

= (2× 5 + 2 × 2)

= 10 + 4

= 14 cm

6) The Perimeter of Rectangle = (21 + 2b)

= (2 × 3 + 2 × 6)

= 6 + 12

= 18 cm

7) The Perimeter of Rectangle = (21 + 2b)

= (2 × 4 + 2 × 6)

= 8 + 12

= 20 cm

8) The Perimeter of Rectangle = (21 + 2b)

= (2 × 5 + 2 × 6)

= (10 + 12)

= 22 cm

9) The Perimeter of Rectangle = (21 + 2b)

= (2 × 8 + 2 × 6)

= 16 + 12

= 28 cm

10) The Perimeter of Rectangle = (21 + 2b)

= (2 × 7 + 2 × 9)

= 14 + 18

= 32 cm

IV. Solve the following:

Question 1.

A rectangular room measure 6m in length and 4m in breadth. Find the perimeter of the room.

Answer:

Length = 6m

Breadth = 4m

The Perimeter of a room = (21 + 2b) units

= (2 × 6 + 2 × 4)

= 12 + 8

= 20 meters

Question 2.

A rectangular field has a length of 150m and breadth 120m. Find the perimeter of the field.

Answer:

The Perimeter of the field = (21 + 2b) units

= (2 × 150 + 2 × 120)

= 300 + 240

= 540 meters

Question 3.

A rectangular garden measures 80m in length and 50m in breadth. Find its perimeter. If the garden has to be fenced 5 rounds with barbed wire, what is the length of the wire required?

Answer:

The Perimeter of Rectangular Garden

= (21 + 2b) units

= (2 × 80 + 2 × 50)

= 160 + 100 = 260 meters

The Garden has to be fenered 5rounds with barbed wire = 260 × 5

= 1300 metres

Question 4.

An auditorium measures 80m in length and 30 min breadth. If the walls of the auditorium have to be decorated with colored buntings 4 times, find the length of buntings required. If the cost of 1m of buntings is Rs. 15, what is the total cost of the buntings used to decorate the auditorium?

Answer:

The Perimeter of Auditorium = (21 + 2b) units = (2 × 80 + 2 × 30)

= 160 + 60

= 220 metres

Auditorium walls have to be decorated with colour buntings = 220 × 4 = 880 metres The cost of the buntings used to decorate the auditorium = 880 × 15 = 13,220

The cost of 1 metre of bunting = Rs 15

Question 5.

Srilatha, during her morning walk, goes round a rectangular park 3 times. If the length and breadth of the park are 320 m and 210 m respectively, calculate the distance she has covered.

Answer:

The Perimeter of Rectangular Parks

= (21 + 2b) units

= (2 × 320 + 2 × 210)

= 640 + 420

= 1060 metres

Srilatha walks round Rectangular park

= 3 times

= 1060 × 3

= 3180 metres

Srilatha walks 3180 metres of distance

### KSEEB Class 5 Maths Perimeter and Area Ex 9.2

I. Answer orally:

Question 1.

Mention the two dimensions of a square.

Answer:

Length × width

Question 2.

How many equal sides are there in a square?

Answer:

4

Question 3.

How many times is the perimeter of a square to its length?

Answer:

Four times

Question 4.

What is the perimeter of a square of length 5 cm?

Answer:

The perimeter of a square

= 4 × 1

= 4 × 5

= 20 cm

II. The rectangle given below are divided into squares of unit length. Find their areas:

The perimeter of a square

= 4 × 1

= 4 × 14

= 56 cm

The perimeter of a square

= 4 × 1

= 4 × 50

= 200cm

The perimeter of a square

= 4 × 1

= 4 × 52

= 208 cm

The perimeter of a square

= 4 × 1

= 4 × 45

= 180 cm

The perimeter of a square

= 4 × 1

= 4 × 35

= 120 cm

III. Lengths of the squares are given in the following table. Find their perimeters.

a) The perimeter o f a square = 4 × 1 = 4 × 3 = 12 cm

b) The perimeter of a square = 4 × 1 = 4 × 5 = 20 cm

c) The perimeter of a square = 4 × 1 = 4 × 11 = 44 cm

d) The perimeter of a square = 4 × 18 = 72 cm

e) The perimeter of a square = 4 × 25 = 100 cm

f) The perimeter of a square = 4 × 30 = 120 cm

g) The perimeter of a square = 4 × 41 = 164 cm

i) The perimeter of a square = 4 × 55 = 220 cm

j) The perimeter of a square = 4 × 63 = 252 cm

k) The perimeter of a square = 4 × 92 = 368 cm

IV. Solve the following problems:

Question 1.

The length of a square room is 15m. Find its perimeter.

Answer:

The perimeter of a square room

= 4 × 1

= 4 × 15

= 60 meter

Question 2.

Rama, runs 4 times around a square park of length 85 m. What is the total distance he covers?

Answer:

The perimeter of a square park

= 4 × 1

= 4 × 85

= 340 mt

Rama runs 4 times around a park

= 340 × 4

= 1360mt

Question 3.

The length of a square room is 16m. The walls of the room should be tied with colored buntings 4 times. Find the total length of buntings required.

Answer:

The perimeter of a square room

= 4 × 1

= 4 × 6

= 64 cm

The room should be tied with colored buntings 4 times

= 64 × 4

= 256 mt

Question 4.

The length of a square ground is 70m. Find its perimeter. (Additional Que)

Answer:

The perimeter of a square ground

= 4 × 1

= 4 × 70

= 280 mt

Question 5.

The length of a square playground is 30m. Find its perimeter. (Additional Question)

Answer:

The perimeter of a square playground

= 4 × 30

= 120 mt

### KSEEB Class 5 Maths Perimeter and Area Ex 9.3

I. Answer orally:

Question 1.

What is the unit of area?

Answer:

Square units.

Question 2.

What is the space within the boundary of a plane figure called?

Answer:

Area

Question 3.

What is the area of a unit square?

Answer:

Unit square

II. The rectangle given below are divided into squares of unit length. Find their areas:

Area of Rectangle

= (1 × b) units

= 3 × 4

= 12 sq.units

Area of Rectangle

= (1 × b) units

= 5 × 3

= 15 sq.units

Area of Rectangle

= (1 × b) units

= 6 × 4

= 24 sq.units

Area of Rectangle

= (1 × b) units

= 7 × 3

= 21 sq.units

Area of Rectangle

= (1 × b) units

= 8 × 4 = 32 sq.units

III. The length and breadth of the rectangles are given below. Calculate their areas:

(1) Area of Reactangle

= 1 × b

= 2 × 3

= 6 sq.cm

(2) Area of Reactangle

= 1 × b

= 2 × 4

= 8 sq.cm

(3) Area of Reactangle

= 1 × b

= 3 × 4

= 12 sq.cm

(4) Area ofRectangle

= 1 × b

= 5 × 4

= 20 Sq.cm

(5) Area ofRectangle

= 1 × b

= 5 × 2

= 10 Sq.cm

(6) Area of Rectangle

= 1 × b

= 3 × 6

= 18 Sq.cm

(7) Area of Rectangle

= 1 × b

= 4 × 6

= 24 Sq.cm

(8) Area ofRectangle

= 1 × b

= 5 × 6 = 30 Sq.cm

(9) Area of Rectangle

= 1 × b

= 8 × 6

= 48 Sq.cm

(10) Area ofRectangle

= 1 × b

= 7 × 9

= 63 Sq.cm

IV. Find the area of the figures given below:

Area ofRectangle

= 1 × b

= 70 × 90

= 6300 Sq.cm

Area of Rectangle

= 1 × b

= 60 × 20

= 1200 Sq.cm

Area of Rectangle

= 1 × b

= 153 × 122

= 18,666 Sq.cm

Area of Rectangle

= 1 × b

= 3 × 6

= 18 Sq.cm

Area of Rectangle

= 1 × b

= 92 × 80

= 7,360 Sq.cm

V. Solve the following problems:

Question 1.

A farmer has a rectangular land length 250m and breadth 180m. Find the area of the land.

Answer:

Area of the land

= 1 × b

= 250 × 180

= 45,000 Sq.cm

Question 2.

A carpet is needed to cover the entire area of a room. If the length of the room is 16m and breadth 5m, find the area of the carpet required.

Answer:

Area of the carpet

= 1 × b

= 16 × 5

= 80 Sq.cm

Question 3.

An auditorium measures 25m in length and 18m in breadth. How many slabs of stones of 3m × 1m are required to cover the floor of the auditorium?

Answer:

Area of Auditorium

= 1 × b

= 25 × 18

= 450 Sq.cm

The size of the slab stane

= 3m × 1m

= 3m

The number of slab stanes

= 150

Question 4.

A rectangular plot’s length is 25m and breadth is 15m. Find the area of the plot. If 1 square meter of the plot costs Rs. 250, what is the total value of the plot?

Answer:

Area of the plot = 1 × b

= 25 × 15

= 375 Sq.cm

1 Sq.mt of the plot Rs 250

375 Sq.mt of the plot = 375 × 250

= 93,750

Question 5.

A rectangular room’s length is 20m and breadth is 11m. How many tiles of 2m × 1m are required to cover the floor of the room?

Answer:

Area of room

= 1 × b

= 20 × 11

= 220 Sq.cm

The number of tiles to cover the floor of the room

= 2m × 1m

= 2m

### KSEEB Class 5 Maths Perimeter and Area Ex 9.4

I. Answer orally:

Question 1.

What is the total space within the boundary of a square called?

Answer:

Area

Question 2.

What is the unit of area?

Answer:

(1 × 1)

Question 3.

What is the area of a square?

Answer:

Sq.unit

II. Find the area of the figures given below:

Area of a square

= 1 × 1

= 52 × 52

= 2,704 Sq.cm

Area of a square

= 1 × 1

= 50 × 50

= 2,500 Sq.cm

Area of a square

= 1 × 1

= 14 × 14

= 136 Sq.cm

Area of a square

= 1 × 1

= 45 × 45

= 2,025 Sq.cm

Area of a square

= 1 × 1

= 35 × 35

= 1,225 Sq.cm

III. The measure of one side of the squares are given below. Find their areas.

(1) Area of a Square

= 1 × 1

= 3 × 3 Sq.cm

(2) Area of a Square

= 1 × 1

= 5 × 5

= 25 Sq.cm

(3) Area of a Square

= 1 × 1

= 11 × 11

= 121 Sq.cm

(4) Area of a Square

= 1 × 1

= 18 × 18

= 324 Sq.cm

(5) Area of a Square

= 1 × 1

= 25 × 25

= 625 Sq.cm

(6) Area of a Square

= 1 × 1

= 30 × 30

= 900 Sq.cm

(7) Area of a Square

= 1 × 1

= 41 × 41

= 1,681 Sq.cm

(8) Area ofa Square

= 1 × 1

= 55 × 55

= 3,025 Sq.cm

(9) Area of a Square

= 1 × 1

= 63 × 63

= 3,969 Sq.cm

(10) Area ofa Square

= 1 × 1

= 92 × 92

= 8464 Sq.cm

IV. Solve the following problems:

Question 1.

The length of a square room is 6m. What is the area of the floor of the room?

Answer:

Area of the floor of the room

= 1 × 1

= 6 × 6

= 36 sq.mt

Question 2.

The length of a square paper is 21 cm. What is its area?

Answer:

Area of a square paper

= 1 × 1

= 21 × 21

= 441 sq.cm

Question 3.

The length of a square canvas cloth is 15m. Find the area of the cloth?

Answer:

Area of the cloth

= 1 × 1

= 15 × 15

= 225 Sq.mt

Question 4.

The length of a square room is 8m. How many granite stones of 2m × 1m are required to cover the floor of the room?

Answer:

Area of a square room

= 1 × 1

= 8 × 8

= 64 Sq.mt

The number of granites

= 2m × 1m

= 2m

Question 5.

The length of a square room is 400cm. How many square tiles of 10cm in length, are required to cover the floor of the room.

Answer:

Area of a square

= 1 × 1

= 400 × 400

= 1600 sq.cm

The length of a square tile = 10cm

The number of tiles to cover 1,60,000

Area of tiles = 10 × 10

= 100 sq.cm