Students can Download Chapter 2 Fractions and Decimals Ex 2.2, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.
Karnataka State Syllabus Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.2
Question 1.
Which of the drawings (a) to (d) show :
Solution:
Question 2.
Some pictures (a) to (c) are given below. Tell which of them show :
Solution:
Question 3.
Multiply and reduce to lowest form and convert into a mixed fraction :
Solution:
iii)
Solution:
iv)
Solution:
v)
Solution:
vi)
Solution:
vii)
Solution:
viii)
Solution:
ix)
Solution:
Question 4.
i) \(\frac{1}{2}\) of the circles in box (a)
Solution:
ii) \(\frac{2}{3}\) of the triangle in box(b)
Solution:
Total triangles = 3 × 3 = 9
we need to shade \(\frac{2}{3}\) triangles number of circles to shade
∴ (shading triangles = 6)
iii) \(\frac{3}{5}\) of the squares in box (c).
Solution:
Total squares = 5 × 3 = 15
we need to shade \(\frac{3}{5}\) squares.
number of squares to shade
(∴ So shading squares = 9)
Question 5.
Find:
a)
Solution:
ii)
Solution:
b)
Solution:
ii)
Solution:
c)
Solution:
ii)
Solution:
d)
Solution:
ii)
Solution:
Question 6.
Multiply and express a mixed fraction:
a)
Solution:
b)
Solution:
c)
Solution:
d)
Solution:
e)
Solution:
f)
Solution:
Question 7.
Find:
a)
Solution:
ii)
Solution:
b) 
Solution:
ii)
Solution:
Question 8.
Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained 5 litres of water. Vidya consumed \(\frac{2}{5}\) of the water. Pratap consumed the remaining water,
i) How much water did Vidya drink ?
Solution:
Total water = 5 liters
Given that,
Vidya drank \(\frac{2}{5}\) of the water.
∴ Water Vidya drank = \(\frac{2}{5}\) × Total water
(∴ Vidya drank 2 liters of water)
(ii) What fraction of the quantity of water did Pratap drink ?
Solution:
Now,
Water pratap drink = Total water – water vidhya drink
= 5 – 2
= 3 liters
∴ Pratap drink 3 liters of water
fraction of total water pratap drink =
